Question

Time = 3/2
years
Principal = 1200. Rate
Rate = 11% per annum,

Find the simple interest and amout​

Answer 1

Answer:

✥Formula used:

$S.I= \frac{P \times R \times T}{100}$

✥Solution:

$➺S.I = \frac{12 \cancel{00 }\times 11 \times 3}{ 1 \cancel{00} \times 2}$

$➺S.I = \frac{ \cancel{12} \: ^{6} \times 11 \times 3}{ \cancel{2} }$

$➺S.I =6 \times 11 \times 3 \\ \\➺S.I =ʀs.198$

Therefore, The simple Interest is Rs.198

Amount: (198+1200) = 1398

Therefore, The Amount is Rs.1398

Answer 2

Answer:

SI=p×r×t/100

1200 x 11% × 3/2

100

SI= 198 %