Science, asked by Anonymous, 3 months ago

time : 4 sec ,mass : 7000 kg, velocity : 36 km / hr. find the force applied to Stop the bus.( answer is - 17500N ) I will follow you if you can answer this questions ​

Answers

Answered by Anonymous
3

Answer:

Mass of the bus = 7000 kg

Time = 4 sec

Velocity of the bus = 36 km/hr

To Find :

The Force applied to stop the bus

Solution :

using first equation of motion , v = u + at

Here ,

v is final velocity

u is initial velocity

a is acceleration

t is time

We have ,

v = 0 {since it comes to rest}

u = 36 km/hr = 36(5/18) m/s = 10 m/s

t = 4 sec

Mass = 7000 kg

Substituting the values ;

➙ 0 = 10 + (F/m)(4) { ∵ a = F/m}

➙ 0 = 10 + (F/7000)(4)

➙ 0 = 10 + (4F/7000)

➙ 0 = (70000 + 4F)/7000

➙ 0 = 70000 + 4F

➙ -70000 = 4F

➙ F = -70000/4

➙ F = -17500 N \begin{gathered}\\\end{gathered}

Hence ,

The Force that should be applied to bring the bus to rest is -17,500

Answered by Anonymous
0

Answer:

Given data:

Mass of stone(m)=7000 kg

Distance(S)=400 meter

Time(t)=20 second

1) We have to find the acceleration of the truck

So from the equation of motion S=ut+21a×t2, whereu=0

 S=21a×t2

a=t22×S=20×202×400=2sec2m

2) Force acting on truck

So,from newton's 2nd law of motion

F=ma=7000×2=14000N=14kN

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