Question

time : 4 sec ,mass : 7000 kg, velocity : 36 km / hr. find the force applied to Stop the bus.( answer is - 17500N )​

Answer 1

$\huge\bold{Answer}$

Given :

• Mass of the bus = 700 kg
• Time = 4 second
• Velocity of the bust = 36 km/hr

To Find :

• The Force applied to stop the bus

Solution :

using first equation of motion ,

V = v + at

Here ,

• V is final velocity
• U is intial velocity
• A is acceleration
• T is time

We have ,

• V = 0 {since it comes to root}

• V = 36 km/hr= 36(5/18) m/s = 10 m/s

• T = 4 second

• Mass = 7000 kg

Substituting the values ;

➙ 0 = 10 + (F/m)(4) { :• a = F/m}

➙ 0 = 10 + (F/7000)(4)

➙ 0 = 10 + (F4/7000)

➙ 0 = (70000 + 4F)/7000

➙ 0 = 70000 + 4F

➙ -70000 = 4F

➙ F = -70000/4

➙ F = -17500 N

Hence ,

• The Force that should be applied to bring the bus to rest is -17,500 N

Answer 2

Answer:

$\large\bf\red{❅\:Answer\:❅}$

Explanation:

Given :

Mass of the bus = 700 kg

Time = 4 second

Velocity of the bust = 36 km/hr

To Find :

The Force applied to stop the bus

Solution :

using first equation of motion ,

V = v + at

Here ,

V is final velocity

U is intial velocity

A is acceleration

T is time

We have ,

V = 0 {since it comes to root}

V = 36 km/hr= 36(5/18) m/s = 10 m/s

T = 4 second

Mass = 7000 kg

Substituting the values ;

➙ 0 = 10 + (F/m)(4) { :• a = F/m}

➙ 0 = 10 + (F/7000)(4)

➙ 0 = 10 + (F4/7000)

➙ 0 = (70000 + 4F)/7000

➙ 0 = 70000 + 4F

➙ -70000 = 4F

➙ F = -70000/4

➙ F = -17500 N

Hence ,

The Force that should be applied to bring the bus to rest is -17,500 N

༄ᏂᎧᎮᏋᏕ ᎥᏖ'Ꮥ ᏂᏋᏝᎮᏕ ᎩᎧᏬ♥