Time of flight of an object projected with speed 20 m/s and an angle 30° with horizontal then time of flight is
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Dear student,
It is given that the initial speed of projectile is 20 m/s and the angle of elevation is 30°. We need to find the time of flight.
By the concepts of projectile motion in 2 dimension, we know that, time of flight of a projectile is given by;
T = 2u sin∅/g
Putting the given values in the equation, we obtain;
T = 20 × sin 30°/ 10
T = 20 × 2 /2 × 10
T = 2 seconds
Hence, the time of flight for the projectile is 2 seconds.
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