Math, asked by phandleesihle, 1 day ago

Time of SPQR in terms of x. Statement Reason

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Answered by oamrendra03

2

Side pq = 2x + 10
Pr = 4x + 2
Qr = 12 - 6x

Perimeter =( 2x+10)+(4x+2)+(12-6x)
24 - 2x = perimeter
X = 24 / 2
X = 12

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