Question

time period?
A certain sum amounts to 2,970.25 in two years at 9% per annum compounded
annually. Find the sum.
annum for three years​

Answer 1

${ \underline{ \underline{ \bf{ \red{ \large{Answer :-}}}}}}$

• Sum of annum for 3 years is 2500.

${ \underline{ \underline{ \bf{ \orange{ \large{ Given :-}}}}}}$

• Amount = 2970.25
• n = 2 year's
• r = 9%

${ \underline{ \underline{ \bf{ \blue{ \large{ Explanation :-}}}}}}$

We know that,

$: \implies\sf \: A = P ({1 + \dfrac{r}{100} })^{n} \\ \\ : \implies\sf \: 2970.25 = P ({1 + \dfrac{9}{100} })^{2} \\ \\ : \implies\sf \: 2970.25 = P ({ \dfrac{109}{100} })^{2} \\ \\ : \implies\sf \: 2970.25 = P ({1.181 }) \\ \\ : \implies\sf \: P = 2500$

Therefore, the sum annum for 3 years is 2500.

Answer 2

$\sf{\huge{\bold{\pink{\bigstar{\boxed{\boxed{Question}}}}}}}$

• A certain sum amounts to 2,970.25 in two years at 9% per annum compounded
• annually. Find the sum.

$\sf{\huge{\bold{\pink{\bigstar{\boxed{\boxed{Solution}}}}}}}$

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• amount after 2 years = Rs.2970.25
• Rate % = 9%

$\sf{\bold{\blue{\underline{\underline{To\:Find}}}}}$

• principle =????

$\sf{\bold{\purple{\underline{\underline{Solution}}}}}$

$\sf{\bold{\red{\boxed{amount = principle(1 +\dfrac{r}{100})^{time} }}}}$

$\sf{2970.25 = principle(1 +\dfrac{9}{100})^2}$

$\sf{\dfrac{297025}{ 100} = principle({1.09})^2}$

$\sf{\dfrac{297025}{ 100} = principle (1.1881)}$

$\sf{\dfrac{297025}{ 100} = principle (\dfrac{11881}{1000})}$

$\sf{principle = \dfrac{297025\times100\cancel{00}}{11881\times \cancel{100}}}$

$\sf{principle = \dfrac{\cancel{297025}\times 100}{\cancel{11881}}}$

$\sf{principle = 25\times 100}$

$\sf{principle = 2500}$

$\sf{\bold{\orange{\boxed{principle = Rs.2500}}}}$

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