Question

Time period of a pendulum is 20 second find its length, if g =10m/s²​

Answer 1

$\huge\boxed{\underline{\underline{\green{\tt Solution}}}} </p><p>$

Here

T = Time = 20

g = 10

We know that

$T = 2\pi \sqrt{ \frac{l}{g} }$

$\implies \: 20 = 2\pi \sqrt{ \frac{l}{10} }$

$\implies \: \sqrt{ \frac{l}{g} } = \frac{10}{\pi}$

$\implies \: \: l = \frac{100}{ {\pi}^{2} } \times 10 = \frac{1000}{ {\pi}^{2} } = 101.24$

So the required length = 101.24 cm

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Answer 2

Explanation:

Using Time period formulae :-

T=2π√l/g

Now, T=20s

g=10m/s² π=22/7

Now, 20=2×22/7×√l/10

Squaring both side

400×49×10=4×22×22×L

=> L=196000/1936

=101.2396m (approx.)

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