Question

time period of a simple pendulum in a freely falling lift will be

Answer 1

A lift is falling under gravity, what is the time period of the pendulum attached to its ceiling? During free fall the body feels weightlessness inside the lift. Hence g = 0. So time period T = 2π(L/g)½ = 2π(L/0) ½ = ∞.

Answer 2

The time period of a simple pendulum in a freely falling lift will be infite(∞).

Explanation:

To find, the time period of a simple pendulum in a freely falling lift = ?

We know that,

 Time period, t = $2\pi \sqrt{\dfrac{l}{g}}$

Where, t is the time period and

g is the acceleration due to gravity

During free fall the body feels weightless inside the lift.

g = 0

 ∴ Time period, t = $2\pi \sqrt{\dfrac{l}{0}$

$=2\pi \sqrt{\infty}$

$=\infty$

Hence, the time period of a simple pendulum in a freely falling lift will be infite(∞).