Question

time period of an oscillating drop of radius r density p and surface tension s is T= k underrooot pr^3 /s check the correctness of the relation​

Answer 1

Given:

The time period of an oscillating drop of radius r density p and surface tension s is T= k underrooot pr^3 /s  

To find:

Check the correctness of the relation​

Solution:

From given, we have,

The time period of an oscillating drop of radius r density p and surface tension s is T= k underrooot pr^3 /s  

here, we use the dimensional equations to find the correctness of the given equation.

T= k underrooot pr^3 /s  

LHS:

T = [T]

RHS:

k underrooot pr^3 /s = underroot [M^{-1}L^{-3}[L^3] / [M^1L^0T^{-2}] = [T]

k underrooot pr^3 /s = [T]

As LHS = RHS . the given relation is correct.

Answer 2

Answer:

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