time period of an oscillating drop of radius r density p and surface tension s is T= k underrooot pr^3 /s check the correctness of the relation
Answers
Answered by
3
Answer:
Time period of an oscillating drop of radius r, density ρ and surface tension S is t=K√ρr3S. Check the correctness of this relation. As dimensions on both sides are same, the relation is correct.
Similar questions