Physics, asked by rampalgoth1015, 10 months ago

time period of an oscillating drop of radius r density p and surface tension s is T= k underrooot pr^3 /s check the correctness of the relation​

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Answered by itzankit21
3

Answer:

Time period of an oscillating drop of radius r, density ρ and surface tension S is t=K√ρr3S. Check the correctness of this relation. As dimensions on both sides are same, the relation is correct.

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