Question

Time period of simple pendulum at a planet is 2 sec. Length of simple pendulum is 2 meter. Find the value of g at that planet (in m/s2

JEE Main 2021 [ 25 Feburary Shift 1]

Answer 1

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Answer 2

Answer:

g = 2π² m/s²

Explanation:

Given,

Time period of simple pendulum at a planet is 2 sec.

Length of simple pendulum is 2 meter.

To find: The value of g at that planet (in m/s^2)

Solution:

Time period is given as:

T = 2π√ (l/g)

or, g = 4π² l / T²

here, l = 2 , T = 2

Substituting the values,

g = 4π²×2/2² = 2π²

Therefore,  Value of g at that planet is 2π² m/s².