Question

Time period of two pendulum are in the ratio of 1.28:0.32. Calculate the ratio of lengths .

pls send answer in steps
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Answer 1

Answer:

Answer:

16

Explanation:

time period of simple pendulum is given by the equation,

T = 2 pi * root of ( l /g )  

where, l ----> length

        T----> time period

       g----> acceleration due to gravity

and pi = 3.14

In the above equation ,  g and pi are constants ( g = 9.8 m/s^2)

so we can write the above equation as,

T  \alphaα \sqrt{l

that is ,

T1 / T2 = \sqrt{l1/l2

given in the qs that  ,   T1 / T2 = 1.28 / 0.32

therefore applying the values in the equation and after that taking square of both sides we get,

1.28^2 / 0.32 ^2 = l1 / l2

solving this we get,

l1 / l2 = 16

Answer 2

Answer:

1.6384:0.1024, T=2π√1|√g, T~1^2.