Question

Time periods of two pendulums are in the ratio 1.28 : 0.32. Calculate the ratio of lengths.

Answer 1

Answer:

16

Explanation:

time period of simple pendulum is given by the equation,

T = 2 pi * root of ( l /g )  

where, l ----> length

       T----> time period

      g----> acceleration due to gravity

and pi = 3.14

In the above equation ,  g and pi are constants ( g = 9.8 m/s^2)

so we can write the above equation as,

T    

that is ,

T1 / T2 =  

given in the qs that  ,   T1 / T2 = 1.28 / 0.32

therefore applying the values in the equation and after that taking square of both sides we get,

1.28^2 / 0.32 ^2 = l1 / l2

solving this we get,

l1 / l2 = 16

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hope it help u