Question

Time required to stop a car moving with a velocity of 20 m/sec within a distance of 40 m is

Answer 1

using third equation we will find acceleration
${v }^{2} = {u}^{2} + 2as \\ 0 = 400 - 80a \\ so \: a = 5$
now using first equation we will find time
v=u+at
0=20-5t
so t=4 seconds
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