Physics, asked by samvart13978, 28 days ago

Time t(s) - 2 4 6 8
Position x(m) - 4 8 12 16
Also, tell the kind of motion shown by the above data.

Answers

Answered by kashvichaurasia819
2

Answer:

Answer

i) So to find the position of the object at time 20 second, we draw a line parallel to y-axis from time 20 and take the point where it intersects then again draw a line parallel to the x-axis, we get the distance where it intersects the y-axis.

Here the position is 8 meters from starting.

ii) Distance travel in 12 seconds by the object is 6 meters.

iii) Since average speed of object is define as total distance covered by object by total time take. So here total distance is 8 m and the total time is 20 second,

Average speed =

= 0.4 m/s

Kashuuu~

Answered by AngeIianDevil
19

\Large\mathtt\green{ }\huge\underline\mathtt\red{Answer : }

Velocity for first 4s= (4-0)/(4-0)= 1 m/s

Velocity for next 4s= 0 (Slope is 0)

Velocity for last 6s= (6-0)/(16-10)= -1 m/s

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