Math, asked by neerajsharma1608, 2 months ago


Time taken by 3 Girl and 2 Boys to complete a work is 4 days
the work done 5 girl is 7 days more than work done by 4 boys. The number of days in
which work is completed by a boy and girl working together is? ​

Answers

Answered by RvChaudharY50
0

Given :- Time taken by 3 Girl and 2 Boys to complete a work is 4 days . The work done by 5 girl is 7 days more than work done by 4 boys.

To Find :- The number of days in which work is completed by a boy and girl working together is ?

Answer :-

Let us assume that,

  • Efficiency of a girl = G unit/day .
  • Efficiency of a boy = B unit/day .

so,

→ Total work = 4 * (3G + 2B) units .

now,

→ 5G completes the total work in = {(12G + 8B)/5G} days .

and,

→ 4B completes the total work in = {(12G + 8B)/4B} days .

A/q,

→ {(12G + 8B)/5G} - {(12G + 8B)/4B} = 7

→ (48GB + 32B² - 60G² + 40GB)/20GB = 7

→ 32B² - 60G² + 88GB = 140GB

→ 4(8B² - 15G²) = 140GB - 88GB

→ 8B² - 15G² = 13 .

given data is incorrect to solve the problem .

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Answered by niyatiinn
0

Answer:

Given :- Time taken by 3 Girl and 2 Boys to complete a work is 4 days . The work done by 5 girl is 7 days more than work done by 4 boys.  

To Find :- The number of days in which work is completed by a boy and girl working together is ?  

Answer :-  

Let us assume that,  

Efficiency of a girl = G unit/day .

Efficiency of a boy = B unit/day .

so,  

→ Total work = 4 * (3G + 2B) units .  

now,  

→ 5G completes the total work in = {(12G + 8B)/5G} days .  

and,  

→ 4B completes the total work in = {(12G + 8B)/4B} days .  

A/q,  

→ {(12G + 8B)/5G} - {(12G + 8B)/4B} = 7  

→ (48GB + 32B² - 60G² + 40GB)/20GB = 7  

→ 32B² - 60G² + 88GB = 140GB  

→ 4(8B² - 15G²) = 140GB - 88GB  

→ 8B² - 15G² = 13 .  

given data is incorrect to solve the problem .

Step-by-step explanation:

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