Question

time taken by 836W water to heat one litre of water from 0 degree Celsius to 40 degree Celsius

Answer 1

heat required by water = heat emitted by heater
i.e  ms∆T = power × time (since, heat = power × time)
= time = ms∆T / power
= time = {1000× 4.186 × (40-10)} / 836 (1 litre = 1kg = 1000 g)
= time = 150 sec.


i hope it will help you
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Answer 2

Answer:

Thank u

Explanation: