Physics, asked by deepakmaliindi28, 1 year ago

Time taken by a 836W heater to heat one liter of water from 10∘Cto40∘C is

Answers

Answered by sprx7tmp8np5g
2
836 w
∆t = 30°c
power = heat/time = 836
heat = m s ∆t = 1×4.12×1000×30 = 126300 J
time = heat/power = 126300/836 = 151.07 seconds
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