Time taken by a plane moving with speed 90km/hr to cover a distance of 500m is
Answers
Answered by
0
We have,
speed, v = 90 kmh-1 = 90 × 5/18 = 25 ms-1
distance, s = 500 m
v = s/t
therefore, t = s/v = 500/25 = 20 s
Therefore the time taken by the plane is 20 s.
Hope this helps
speed, v = 90 kmh-1 = 90 × 5/18 = 25 ms-1
distance, s = 500 m
v = s/t
therefore, t = s/v = 500/25 = 20 s
Therefore the time taken by the plane is 20 s.
Hope this helps
Similar questions