Math, asked by gargrajni1997, 10 months ago

Time taken by Om to cover a
distance of x km at the speed
of 30 kmph is equal to the time
taken by Shyam in covering a
distance of (x - 10) km at the
speed of 25 kmph. Find the
distance Om has travelled.
(1) 90 lon (2) 60 km
(3) 54 km (4) 80 km
(5) 45 km

Answers

Answered by zubiyamomin
2

I think it should. be 54...I am not sure

Answered by JimMoriarty
0

Answer:

Given,

distance covered by Om = x km

distance covered by Shyam = (x-10) km

Time taken by Om = Time taken by Shyam

T(om) = T(shyam)

d/s = d/s

x/30 = (x-10)/25

x/6 = (x-10)/5

5x = 6x-60

6x-5x = 60

x = 60

distance covered by Om = x km = 60km.

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