Time taken by Om to cover a
distance of x km at the speed
of 30 kmph is equal to the time
taken by Shyam in covering a
distance of (x - 10) km at the
speed of 25 kmph. Find the
distance Om has travelled.
(1) 90 lon (2) 60 km
(3) 54 km (4) 80 km
(5) 45 km
Answers
Answered by
2
I think it should. be 54...I am not sure
Answered by
0
Answer:
Given,
distance covered by Om = x km
distance covered by Shyam = (x-10) km
Time taken by Om = Time taken by Shyam
T(om) = T(shyam)
d/s = d/s
x/30 = (x-10)/25
x/6 = (x-10)/5
5x = 6x-60
6x-5x = 60
x = 60
distance covered by Om = x km = 60km.
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