Time taken by the sunlight to pass through a slab of thickness 4 mm and refractive index 1.5 is _______ sec.(A) 2 x 10⁻⁸
(B) 2 x 10⁸
(C) 2 x 10⁻¹¹
(D) 2 x 10¹¹
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Time taken by the sunlight to pass through a slab of thickness 4 mm and refractive index 1.5 is, given
c=3×108ms−1,
μ=32, x=4×10−3m,
vg=cμ =3×1083/2 =2×108ms−1 t=xvg =4×10−32×108 =2×10−11s.
optical distance in a medium of refractive index μ and thickness t is μx and time =μxc here c- is velocity of light,
t=1.5×4×10−33×108 =2×1011 seconds.
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Holla ^_^
☸ Required Answer is ⬇ ⬇⬇ ⬇
⭕ (D) 2 x 10¹¹
Vielen Dank ♥
☸ Required Answer is ⬇ ⬇⬇ ⬇
⭕ (D) 2 x 10¹¹
Vielen Dank ♥
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