Question

Time
Time
A stone is thrown vertically upward with a speed of
40 m/s. The time interval for which particle was
above 40 m from the ground is (g = 10 m/s2)
(1) 4/2s
(2) 8 5
(3) 4s
(4) 2/2 s​

Answer 1

Answer:

bhai iska answer h 4 sec

v = u+at

0= 40 +(-10)t

-40= -10t

t = 4 sec

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