timothy climbed a mountain in two days.timothy spent a total of 14 hours climbing the mountain . on the second day, timothy walked at an average speed that was half a kilometer per hour faster , but was two hours less than what timothy walked on the first day . if the total distance timothy covered during the two days was 52 kms, how many kms per hour did timothy walk on the second day?
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Given: A total of 14 hours climbing the mountain.
To find: How many kms per hour did timothy walk on the second day?
Solution:
- Now we have given that . Timothy spent a total of 14 hours climbing the mountain . on the second day, timothy walked at an average speed that was half a kilometre per hour faster , but was two hours less than what timothy walked on the first day.
- So let time traveled during 1st day be t and time traveled during 2nd day be t - 2 .
- Now the total time is 14 hours, so:
t + t - 2 = 14
2t - 2 = 14
2t = 16
t = 8
- Now we know the formula:
speed x time = distance
- Let the speed be s, so applying this, we get:
s(8) + (s+0.5)(8-2) = 52
8s + 6s + 3 = 52
14s = 49
s = 3.5
- For second day the speed is s + 1/2 so:
3.5 + 1/2 = 4 km/hr
Answer:
So the speed of second day is 4 km/hr.
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