Question

Tina bought a watermelon which weighed 6 kg 700 g. Out of it, she ate 1 kg 300 g with one of her
friend and then distributed 700 g each of her two other friends. What is the weight of the watermelon
that remained with her?​

Answer 1

Answer:

The answer is 4000g or 4kg

Step-by-step explanation:

first she and her friend ate 1.300 kg so 6.700 kg - 11.300 kg=

5.400 kg.

then she distributed it in her two friends so 700 g x 2= 1.400 kg

5.400 kg- 1.400 kg = 4 kg or 4000 g

HOPE IT IS CLEAR TO YOU.

Answer 2

$\boxed{\red{Answer}}$

$4 \: kg$

★ Given :

• The weight of the watermelon while buying is 6 kg 700 g.
• She and her friend ate 1 kg 300 g.
• She distributed 700 g each of her two friends.

★ To Find :

The weight of the remained watermelon.

★ Solution :

The net weight of the watermelon is 6 kg 700 g.

Tina and her friend ate 1 kg 300 g of it.

• So now it remains

$6kg \: 700 \: g \: - 1 \: kg \: 300 \: g \\ = 5 \: kg \: 400 \: g$

$5 \: kg \: 400 \: g \: \\ = (5000 + 400)g \\ = 5400 \: g$

Tina's another two friends got 700 g each.

• So now it remains

$5400 - (700 + 700) \: g \\ = (5400 - 1400) \: g \\ = 4000g \: = 4 \: kg$

Therefore, the answer is 4 kg.