Question

Tina had 20m7cm long cloth she cuts 5m50cmlength of coth from this for making a culal how much cloth is left with her

Answer 1

ANSWER

Length of cloth Tina had

=20 m 5 cm=20 m + 0.05 m [∵

100

1

cm=0.01 m]

=(20+0.05) m=20.05 m

Length of cloth cut of 4 m 50 cm

=4 m+50 cm

=4 m+

100

50

m=4 m+0.50 m [∵

100

1

cm=0.01 m]

=(4+0.50) m=4.50 m

∴ Length of cloth left =20.05 m−4.50 m

=15.55

−

=

1

2

1

9

0

4

5

⋅

⋅

⋅

10

0

5

5

5

0

5

m

m

m

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