Question

Tine valuc of a if f (x)=1/x+ax and f(1/5)= 28/5 (a)3 (b)2 (c)1 (d)0
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Answer 1

Answer:

The answer is option (a)

Step-by-step explanation:

Given $f(x)=\frac{1}{x}+ax$

$\Rightarrow f(\frac{1}{5})=\frac{28}{5}\\\Rightarrow \frac{1}{\frac{1}{5}}+a(\frac{1}{5})\\\Rightarrow 5+\frac{a}{5}=\frac{28}{5}\\\Rightarrow 25+a=28\\\Rightarrow a=28-25=3$

Answer 2

Answer:

solution

$\begin{gathered}\Rightarrow f(\frac{1}{5})=\frac{28}{5}\\\Rightarrow \frac{1}{\frac{1}{5}}+a(\frac{1}{5})\\\Rightarrow 5+\frac{a}{5}=\frac{28}{5}\\\Rightarrow 25+a=28\\\Rightarrow a=28-25=3\end{gathered}$