Question

tinu is younger than pinku by three years . The product of their ages is 180 . find their present ages

Answer 1

$\mathcal{\huge{\underline{\purple{Question:-}}}}$

Tinu is younger than pinku by three years. The product of their ages is 180°. Find their present ages.

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Given :-

• Tina is younger than pinku by three years.

• Product of their ages is 180°.

To Find :-

• Their present ages.

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$\mathcal{\huge{\underline{\purple{Solution:-}}}}$

• Let Pinku's present age be x

• Then, Tinu's age will be x - 3

According to question :-

Product of their ages is 180.

$x(x - 3) = 180$

$= > x {}^{2} - 3x = 180$

$= > x {}^{2} - 3x - 180 = 0$

$= > x {}^{2} - 15x + 12x - 180$

$= > x(x - 15) + 12(x - 15) = 0$

$= > (x + 12)(x - 15) = 0$

$= > x + 12 =0$

$= > x = - 12$

Ignore negative value ........

$= > x - 15 = 0$

$= > x = 15$

$= > x - 3 = 15 - 3 = 12$

Hence, the ages of Pinku and Tinu are 15 and 12 respectively.

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