Question

Tinu takes 9 days more than his father to do a certain piece of work. Together they can do the work in 6 days. How many days will Tinu take alone to do the work ?

Answer using quadratic equation.
Pls answer with calculations. ​

Answer 1

Step-by-step explanation:

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Tinu takes 9 days more than his father to do a certain piece of work. Together they can do the work in 6 days. How many days will Tinu take to do that work alone.

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Correct option is B)

Let Tinu can do work in x days and his father can do work in y days

Then, x−y=9 or x=9+y

Tinu's one day work =

x

1

Father's one day work =

y

1

Then,

x

1

+

y

1

=

6

1

xy

x+y

=

6

1

xy=6(x+y)

y(9+y)=6(9+y+y)

9y+y

2

=54+12y

y

2

−3y−54=0

y=

2

3±

9+216

y=

2

3±15

y=9,−6

x=9+y=9+9=18 days

Hence, Tinu can complete work in 18 days.

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