Question

Tiny water droplets in the air disperse the white light of the sun into a rainbow. What is the energy of a photon from the red portion of the rainbow if it has a frequency of 4.57 × 1014s–1?

Answer 1

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E = hv

E = energy

h= Planck's Constant

v = frequency (actually the Greek letter nu)

E = (6.63 X10^-34 Joule sec)(4.57 X 10^14 /sec) = 3.03 X 10^-19 Joule

Answer 2

Answer:

E=(6.626×10^-34)×(4.57×10^14)

E=3.03×10^-19J

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