tirangle abc similar to triangle def such that area of triangle abc = 36cmsquare and area of triangle def = 49cmsquare then find the ratio of their corresponding sides
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Answered by
5
Answer:
6 : 7
Step-by-step explanation:
ar(abc) / ar(def) = (ab/de)^2
36 / 49 = (ab/de)^2
√36/49 = ab/de
6/7 = ab/de
Answered by
0
The areas of two similar triangles are in the ratio of the squares of the corresponding altitudes.
Let first triangle altitude be x then second one's is x+10
so, Area of first triangle/area of second triangle=altitude of first triangle/altitude of second triangle
so, 49/64=(x/x+10)²
so, (7/8)²=(x/x+10)²
so, 7/8=x/x+10
so, 7(x+10)=8x
so, 7x+70=8x
so, 7x-8x=-70
so, x=70
So, first triangle's altitude is 70 cm
And, the second one's is 80 cm
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