Tire age of a father and his son together are 80 years,
and if the age of the son be double, it will exceed the
father's age by 10 years. Find both their ages.
Answers
Answered by
1
Answer:
SON'S PRESENT AGE : 14 years.
FATHER'S PTESENT AGE: 38 years.
Step-by-step explanation:
Let son's age = x
Two years ago son's age= x-2.
His Father's age at that time = 3(x-2).
Present age of Father = 3x-6+2=3x-4
Two years hence father's age=3x-4+2=3x-2.
Two years hence son's age = x+2.
Given :-5*(x+2)=2*(3x-2)
5x + 10= 6x - 4
10+4=6x-5x
14=x
SON'S PRESENT AGE : 14 years.
FATHER'S PTESENT AGE: 38 years.
Answered by
0
Answer:
son's present age = 14 years
father's present age = 38 years
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