tita is equal to 3 by 5 then find the value of 1 + tan theta divided by 1 minus tan theta
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Answer:
Step-by-step explanation:
As we know
Cos theta = 1/sec theta
Now,
Sec^2 theta = 1+tan^2 theta Now,
= 1+(3/4)^2 cos theta = 4/5
= 1+9/16 1-cos theta/1+cos theta = 1-(4/5)/1+(4/5)
= 16+19/16 = (5-4)/5/(5+4)/5
Sec theta = ✓(25/16) = 1/9
= 5/4
Cos theta = 1/sec theta
= 1/(5/4)
= 4/5
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