Question

Title
2r²-5r+2=0
Find the value of r.​

Answer 1

Answer:

${2r}^{2} - 5r + 2 = 0 \\ \\ = > {2r}^{2} - (4 + 1)r + 2 = 0 \\ \\ = > {2r}^{2} - 4r - r + 2 = 0 \\ \\ = > 2r(r - 2) - 1(r - 2) = 0 \\ \\ = > (r - 2)(2r - 1) = 0 \\ \\ either \: r - 2 = 0 \\ \\ = > r = 2 \\ \\ or \: 2r - 1 = 0 \\ \\ = > 2r = 1 \\ \\ = > r = \frac{1}{2}$

♡ hope it helps ♡

Answer 2

Answer:

2r²-5r+2=0

=>2r²-4r-r+2=0

=>2r(r-2)-1(r-2)=0

=>(2r-1)(r-2)=0

=>2r-1=0 or r-2=0

=>2r=1 or r=2

=>r=½ or r=2