titu is 7 years older than his younger brother.after 5 years,the sum of their ages will be 39. find their present age.
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Answered by
7
Let titu's age = x
his younger brother age = x-7
After 5 years,
titu's age = x+5
his younger brother age = x-7+5 = x-2
Sum = 39
=> x+5 + x-2 = 39
=> 2x + 3 = 39
=> 2x =39-3 = 36
=> x = 36/2
=> x = 18 years
Titu's age = 18 years
His brothers age = 18-7 = 11 years
his younger brother age = x-7
After 5 years,
titu's age = x+5
his younger brother age = x-7+5 = x-2
Sum = 39
=> x+5 + x-2 = 39
=> 2x + 3 = 39
=> 2x =39-3 = 36
=> x = 36/2
=> x = 18 years
Titu's age = 18 years
His brothers age = 18-7 = 11 years
prince2693:
thanks lot
Answered by
10
Let titu's age = x
his younger brother age = x-7
After 5 years,
titu's age = x+5
his younger brother age = x-7+5 = x-2
Sum = 39
=> x+5 + x-2 = 39
=> 2x + 3 = 39
=> 2x =39-3 = 36
=> x = 36/2
=> x = 18 years
Titu's age = 18 years
His brothers age = 18-7 = 11 years.
HOPE SO IT WILL HELP.....
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