Question

tivity:
i.
03
AABD is a triangle in which ZA-90° and seg AC 1 seg BD Show that
i) AB2= BC.BD ii) AD2=BD.CD
iii) AC?=BC.CD
i) In AABD, ZBAD=90°
(Given)
seg AC 1 hypotenuse BD
... In ABCA-AACD - ABAD
(Similarity in Right-angled triangle)
ii) ABCA-ABAD
... (From ))
BC
... (c.s.s.)
BA
=BD.CD
iii) AACD - ABAD
CD
AD
=BD.CD
... (From (1)
(c.s.s.t)
B
iv) ABCA ~AACD
AC
DC
.. ACP
... (From (1)
... (C.S.S.t)
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Answer 1

Answer:

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