Question

Tk
13. In Fig. 15.36, BD = 10 cm,
AC = 12 cm and BC = 26 cm.
(a) Find area of AABC.
(b) Calculate the height AE.
10 cm
12 cm
E
B
26 cm
Fig. 15.36​

Answer 1

Step-by-step explanation:

ABC is right angle triangle therefore

by Pythagoras theorem:-

AB²+BC²=AC²

ΑΒ²=AC²−BC²

ΑΒ²=(26)²−(10)²

ΑΒ²=(26–10)(26+10)

AB²=16*36

AB=√16×36

ΑΒ=4×6

ΑΒ=24cm

hope you help with this answer