Math, asked by AramandlaAvinash, 10 months ago

Tkx + /
7. Find the value of k, if the discriminent of a Q.E. 2x2 - Vkx +
= 0 is 1.​

Answers

Answered by santrammaurya1975
0

Answer:

Given, 2x^2+Kx+3 here it is in the form ax^2+bc+C=0 here a=2, b=K, c=3 if it has two equal roots. then ∆=0 b^2-4ac=0

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