Tn=5-4 n find the first fore terms
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Tn = 5 - 4n
=> a + (n-1) d = 5 - 4n
=> a + (n-1) d = 1 + 4 - 4n
=> a + (n-1) d = 1 - 4(n-1)
On Comparing both sides, we get
a = 1
d = - 4
T1 = a = 1
T2 = a + d = 1 - 4 = - 3
T3 = a + 2d = 1 - 8 = - 7
T4 = a + 3d = 1 - 12 = - 11
=> a + (n-1) d = 5 - 4n
=> a + (n-1) d = 1 + 4 - 4n
=> a + (n-1) d = 1 - 4(n-1)
On Comparing both sides, we get
a = 1
d = - 4
T1 = a = 1
T2 = a + d = 1 - 4 = - 3
T3 = a + 2d = 1 - 8 = - 7
T4 = a + 3d = 1 - 12 = - 11
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