Math, asked by vamshikrishna394, 9 months ago


tne sum of a two digit number and the number obtained by reversing the digit is 66
number differ by 2. find the number. How many such numbers are there ​

Answers

Answered by Anonymous
0

Answer:

Step-by-step explanation:

Numbers are 42  & 24

& reverse of numbers are 24 & 42

Step-by-step explanation:

The sum of a two digit number and the number obtained by reversing the digit is 66 if the digit of the number differ by 2 find the number how many such numbers are there

Let say NUmber is XY

Value = 10X + Y

Reverse of number = YX

Value = 10Y + X

10X + Y + 10Y + X = 66

=> 11X + 11Y =  66

=> X + Y = 6   - eq1

|X - Y| = 2

Case 1

X - Y = 2    - eq2

Adding eq 1 & eq 2

=> 2X = 8 => X  = 4  & Y = 2

Case 2

X - Y = -2    eq 3

Adding Eq 1 & eq 3

=> 2X = 4 => X = 2  & Y = 4

Numbers are 42  & 24

& reverse of numbers are 24 & 42

Read more on Brainly.in - https://brainly.in/question/3096111#readmore

Answered by 8699315433
0

Answer:

frr solution refer to the following attachment.....

Hp it will hlp uuhhhh.....

plss mark as brnliest.......

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