To
1. Radius of the dees of a 10' Hz eyclotron is 0-6 m.
Find the operating magnetic field and the kinetio
energy of the proton beam produced by it.
Solution
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ANSWER
=V=10MHz 10=Hz
B=?
V=
2πM
Bq
or B=
q
2πMV
=
1.6×10
−19
2×(
7
22
)×(1.67×10
−27
)10
7
=0.656T
Now,
E
m
ax=
2M
B
2
q
2
R
2
=
2×1.67×10
−27
(0.656)
2
×(1.67×10
−27
)
2
×(60×10
−2
)
2
=1.19×10
−12
J
=
1.6×10
−19
×10
6
1.19×10
−12
=7.421mev
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