Question

To 4L of 0.2M Sol. Of NaOH 2L of 0.5M NaOH is added . the molarity of resulting solution is

Answer 1

Answer:

4L,0.2 m. 2L,0.5m

NaoH. NaoH

V1 N1+V2+N2+...…..=V total N total

VaNa+VdNd=VtotalNtotal

N=n-factor*majority

N=M

VaMa+VbMb=Vtotal*Mtotal

4L*0.2+2L*0.5

(4L+2L)* Mtotal

Mtotal=0.8+1/6

Mtotal=0.3.

hope it will help you

Answer 2

Answer:

0.3M

Explanation:

0.8×1/6

.............

=0.3M