Question

to 50ml of 0.1n na2co3 soln 150ml of h2o is added . then calculate the normality of resultant soln

Answer 1

we know
N1V1=N2V2
N2=N1V1/V2
N2=.1*50/150
N2=.1/3
N2=.033n

Answer 2

Normality of resultant solution is 0.025 N

Given : Volume of $Na_{2}CO_{3}$ is 50 ml

Normality of solution is 0.1 N

Volume of water added is 150 ml

To Find : Normality of resultant solution

Solution : Normality of resultant solution is 0.025 N

It is given that to 50 ml of 0.2 N o $Na_{2}CO_{3}$ solution 150 ml of water is added

then we have to calculate the normality of resultant solution

Initial volume of the solution (V1) = 50 ml

Initial normality of the solution N1 = 0.1 N

Amount of water added = 150 ml

Final volume of the solution (V2) = 50 +150 = 200 ml

Final normality of the solution N2 =?

According to dilution law

N1 V1 = N2 V2

So  $N2 = \frac{N1 V1}{V2}$

So putting the all the given values in the equation we get

$N2 = \frac{(0.1)(50)}{200}$

N2 = 0.025 N

So normality of resultant solution is 0.025 N

#SPJ3