Question

To a 10 ml of 10-3 n h2so4 solution water has been added to make the total volume

Answer 1

Answer:

N1×V1 = N2 ×V2

10^(-3) × 10  = N2 × 1000

Or, N2= 10^(-5)

For H2So4 normality equals Molarity×2         ( since n factor of H2SO4 IS 2)

Therefore molarity of H2SO4 = 10^(-5)/2.

Now one mole of H2so4 contains 2 moles of H+ ions.

Molarity of H+ = [H+]= 2× molarity of H2SO4= 10^(-5)

Therefore pH=5

Or pOH = 14-5=9

Explanation: