Question

To A 25 Ml Solution, Excess Of Acidified Solution Of Potassium Iodide Was Added. The Iodine Liberated Required 20Ml Of 0.3N Sodium Thiosulphate Solution. Calculate The Volume Strength Of Solution.

Answer 1

ANSWER

Let N be normality of H2O2

20ml of I2=25 ml of0.1NNa2S2O3=20 ml of I2 =25ml of NH2O2

→20ml of I2=25ml of NH2O2

20∗0.1=25N

N=252=0.08

So strength in terms of normality

Normality * Equivalent Mass

=0.08∗17

=1.36 g/L

In terms of percentage =10001.36∗100=0.136

For 100ml of solution 0.136g of H2O2, volume of oxygen given =22.4L

So, 0136g of H2O2=6822400∗0.00136

=0.448ml of oxygen

Strength

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