Question

To a 25ml solution, excess of acidified solution of potassium iodide was added. The iodine liberated required 20ml of 0.3 n sodium thiosulphate solution. Calculate the volume strength of solution. (iitjeeadvanced, 1997)

Answer 1



 

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30ml of a H2O2 solution after acidification required 30 ml of 0.1 N KMnO4 solution for complete oxidation calculate the percentage of H2O2. 

Pls explain the procedure (ans is 0.17%)

one year ago

Answers : (2)

Equivalent weight of H2O2= equivalent weight of KMnO4Equivalent weight of H2O2=0.03×0.1=0.003Wt. of H2O2= 0.003×34/2(n factor of H2O2=2) = 0.051gMass by vol. %= 0.051g/30ml ×100= 0.17%

one year ago

Gram equivalent of H2O2=Gram equivalent of KMnO4Gram equivalent of H2O2=0.03×0.1=0.003Wt. of H2O2=0.003×34/2(n factor of H2O2=2)=0.051gMass by vol.%=0.051g/30ml=0.17% By Shivam Aditya