to a circle of radius 4 centimetre draw two tangents which are inclined to each other at an acute angle of 60 degree
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justification:-
In triangle OAP,
OA = OP = 4cm. (radii of the same circle)
also, AP = 4cm. (radius of the circle with
center A )
therefore triangle OAP is an equilateral triangle
(by definition)
angle PAO = 60
therefore angle BAP = 120
in triangle BAP ,
BA = BP
also angle BAP = 120
angle ABP = angle. APB = 30
similarly we can get ,
angle ABQ = 30
angle PBQ = 60.
justification:-
In triangle OAP,
OA = OP = 4cm. (radii of the same circle)
also, AP = 4cm. (radius of the circle with
center A )
therefore triangle OAP is an equilateral triangle
(by definition)
angle PAO = 60
therefore angle BAP = 120
in triangle BAP ,
BA = BP
also angle BAP = 120
angle ABP = angle. APB = 30
similarly we can get ,
angle ABQ = 30
angle PBQ = 60.
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