Physics, asked by simmi2554, 11 months ago

To a fish in water a bird in air appears to be at 30 cm from the surface it refractive index of water is 4/3 then the true dist. Of the bird from the surface is

Answers

Answered by hyperstomgaming
0

Answer:

Refractive index =real depth/apparent depth

4/3=real depth /30

(4*30)/3=real depth

Real depth=4*10=40cms

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