to A gas А at Occupies a volume of 40.0 dm3 Standard temperature (0°c) and a (1 atm), when pressure is increase up to 3 atm unchanged temperature what would volume? pressure (1 be the new
Answers
Answer:
The ideal gas equation relating pressure (P), volume (V), and absolute temperature (T) is given as:
PV = nRT
Where,
R is the universal gas constant =8.314Jmol
−1
K
−1
n = Number of moles = 1
T = Standard temperature = 273 K
P = Standard pressure = 1 atm =1.013×10
5
Nm
−2
∴V=nRT/P
=1×8.314×273/(1.013×10
5
)
=0.0224m
3
=22.4 litres
Hence, the molar volume of a gas at STP is 22.4 litres.
Answer:
The volume of the pressure at stp is 22.4ltr
Explanation:
The appropriate gas equation relative to pressure (P), volume (V), and total temperature (T) is given as follows:
PV = nRT
There,
R global gas = 8.314Jmol
n = Number of moles = 1
T = Normal temperature = 273 K
P = Normal pressure = 1 atm = 1.013 × 10^5 Nm
∴V = nRT / P
= 1 × 8.314 × 273 / (1.013 × 10^5)
= 0.0224m
= 22.4 liters
Therefore, the molar volume of gas in the STP is 22.4 liters.