To a man walking due west with a speed of 4m/s,
wind appears to blow from the north-east, when he
increases his speed to 7m/s the wind appears to
blow from the north. Find velocity of wind with
respect to ground.
(1) V50
(2) 140
(3) V58
(4) 142
Answers
Velocity of wind with respect to ground is 7.61m/s from direction east of north.
Consider positive x axis as i , negative axis as -i and positive y axis as j and negative y axis -j .
(Bold letters represent vector)
- Velcoity of man = Vm = -Vmj = -4i
Let velocity of wind with respect to ground =
- Vw = v1i +v2j
Initially velocity of wind with respect to man
- Vwm= Vw - Vm = (v1 + 4 )i + v2j
Given the wind is in South west ( its from north east going towards south west)
Therefore, its in 3rd quadrant and makes 45degree with both axis.
In such a vector the i and j components will be equal.
- Therefore, - ( v1 + 4 ) = v2.
Now the man increases his speed to 7m/s.
Then Vwm = ( v1 + 7 ) i + v2j , is in south ( from north ) = -j direction.
Hence
- v1 + 7 = 0 and Vwm = -v2j
- v2 = - ( -7 + 4 ) = 3
Therefore, velocity of wind wrt ground =
- Vw = -7i + 3j.
Velocity of wind is 7.61m/s from direction east of north.
Velocity of wind with respect to ground is 7.61m/s
EXPLANATION
We need to do this sum using vectors.
Velcoity of man = = - = -4i
Let velocity of wind with respect to ground = =
Initially velocity of wind with respect to man
= - = ( + 4 )i + j
Given the wind is in South west
Therefore it lies in the 3rd quadrant and makes a degree of 45°
Thus, i and j components will be equal.
Therefore, - ( + 4 ) =
Now according to the question,he increases his speed to 7m/s.
Then = ( + 7 ) i + j , is in south = -j direction.
Hence
+ 7 = 0 and = -j
= - ( -7 + 4 ) = 3
Therefore, velocity of wind wrt ground =
= -7i + 3j.
Velocity of wind is 7.61m/s from direction east of north.