To a person running at a speed 5 km/hr rain appears to fall vertically. if the actual speed of rain is 10 km/h, then find the angle the actual speed of rain makes with vertical.
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Answered by
3
Given :-
Speed of man = Vm = 5 Km/h
Speed of rain = Vr = 10 Km/h
Vrm = Vr - Vm
|Vr| = √(Vrm)² + (Vm)²
|Vr²| = Vrm² + Vm²
100 = Vrm² + 25
Vrm = √75
Vrm = 5√3
Let the angle = Ø
tanØ = Vm/Vrm
tanØ = 5/5√3
Ø = tan-¹(1/√3)
Ø = tan-¹(1/√3)Ø = 30° Answer.....
Answered by
5
Answer:
Let V be the vel.of the rain drop
The angle of resultant of the vel. of the man when he runs at 10 km/ h & the Vel of rain at 30° from the vertical is given
This will result in Vsine30°= 10
V= 20km/hour.at 30° from vertical.
Explanation:
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